Python Set

Collection of items, in set items are stored in curly { } brackets.

s = {1, 2, 3}

Note: set are unordered, unindexed, and mutable, also it does not allow duplicate values like tuple, list

Access set

s = {1, 2, 3}
print(s)

for item in s:
	print(item)

add()	Add single item to set	s={1, 2, 3} s.add(4) print(s) # {1, 2, 3, 4}
update()	Add multiple items to set	s={1, 2, 3} s.update(4, 5) print(s) # {1, 2, 3, 4, 5}
remove()	Remove item from set, raise an error when item not found	s={1, 2, 3} s.remove(2) print(s) # {1, 3}
discard()	Remove item from set, and does not raise an error when item not found	s={1, 2, 3} s.remove(3) print(s) # {1, 2}
clear()	Remove all items from a set	s={1, 2, 3} s.clear() print(s) # {}
pop()	Remove an element from a set	s={1, 2, 3} s.pop print(s) # will remove any item from a set
difference()	Return set of difference of two set(set of items of A which are not in B)	x={1, 2, 3} y={3, 4, 5} print( x.difference(y) ) # {1, 2}
intersection()	Return intersection set of two set (set of common items from set A, B)	x={1, 2, 3} y={3, 4, 5} print( x.intersection(y) ) # {3}
union()	Return set of all items from set A, B	x={1, 2, 3} y={3, 4, 5} print( x.union(y) ) # {1, 2, 3, 4, 5}
issubset()	Return true if one set is subset of other set otherwise false	x={1, 2, 3} y={3} print( y.issubset(x) ) # True
copy()	Return copy of a set	x={1, 2, 3} y=x.copy() print( y ) # {1, 2, 3}